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barneyS New user Virginia 28 Posts |
Hi,
I enjoy doing arithmetically/geometrically based magic tricks for smart/knowledgeable kids (and their parents) at STEM events and Maker Faires. This is all volunteer. The best arithmetic tricks I have involve having the spectator do some arithmetic, under guidance, then tell me a final number that they get. From this I am able to tell them the number that they originally thought of. I try to give an interesting presentation so that the trick isn't just "Think of a number, do some arithmetic, and now the number you thought of was ..." but related in some way to something else. I've read a number of books (Martin Gardner's, William Simon's) and watched some Rick Lax videos on the net. So far, all of the methods in which the spectator reveals a single number lead to the reveal of one or two things. Examples would be a number that the mag wrote down early in the trick, the two values on a pair of dice, etc. Can someone point me to a trick, along these lines, where a single number provided by the spectator will allow a reveal of THREE items? I invented one and have tried it on my friends where it has worked (and they are puzzled about how I did it) but my current presentation is a little boring. I hope to fix that over time. If you know of a book, DVD or YouTube video that has a reveal of 3 items from one number I'd appreciate the pointer! Barney |
hcs Special user Germany, Magdeburg 506 Posts |
To reveal a person, a finger and its phalanx:
The persons (#P) are numbered from 1 to ... The 10 fingers (#F) are numbered from 1 (little finger, left hand) to 10 (little finger, right hand) The 3 phalanxes of a finger (#Ph) are numbered from 1 to 3 One selected person wears the ring on a selected finger on a selected phalanx. You are able to reveal person, finger and phalanx, calculating: 1. #P x 2 2. + 5 3. x 5 4. + #F 5. x 10 6. + #Ph 7. = ? Example: person #P=4 right middle finger #f=8 second phalanx #Ph=2 1. 4 x 2 = 8 2. + 5 = 13 3. x 5 = 65 4. + 8 = 73 5. x 10 = 730 6. + 2 = 732 Subtract secretly 250 732 - 250 = 582 (#P/#F/#Ph) |
hcs Special user Germany, Magdeburg 506 Posts |
A similar trick is the revealing of a birthday - month, day and year.
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Paradise Elite user sheffieldEngland 419 Posts |
Quote:
On Oct 11, 2017, hcs wrote: |
barneyS New user Virginia 28 Posts |
Thanks hcs, I appreciate the thought! You multiply by 10 twice and then add the 3rd number so that each occupies one place in the number (after a necessary subtraction).
My version has only one hidden multiplication by 10 (5, then 2) and I multiply after the final addition, just to obscure the problem as much as possible. There is no subtraction. My plan was to give a short talk on my method at next April's Gathering 4 Gardner in Atlanta, though I don't know if they would want to make program space for such a simple thing. And, finally, Paradise: I didn't see any post under your name besides the quote of the hcs method. Do you want to repost? |
hcs Special user Germany, Magdeburg 506 Posts |
Thank you very much for your kind words!
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Sixten Inner circle Floral Park, NY, U.S.A. 4654 Posts |
(A tiny correction)
Subtract secretly 250: 732-250=482 (#P/#F/#PH) & Thank You, hcs! |
hcs Special user Germany, Magdeburg 506 Posts |
Sixten, thank you very much for your carefully reading!
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Sixten Inner circle Floral Park, NY, U.S.A. 4654 Posts |
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