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thoughtsexplorer![]() Elite user Elite... not D-Lite! 424 Posts ![]() |
How many people do you need to bring together (according to terms and theory of probability) so that 2 of them celebrate their birthday on the same day?
hint: 356 is obvious, but wrong |
Slim King![]() Eternal Order Orlando 18350 Posts ![]() |
Less than 30 I think. Somewhere around there. I think that there is a thread on this somewhere too?
THE MAN THE SKEPTICS REFUSE TO TEST FOR ONE MILLION DOLLARS.. The Worlds Foremost Authority on Houdini's Life after Death.....
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Mikey-Flys![]() Regular user Edmonton, Alberta 179 Posts ![]() |
My math may be off but I get ....
23 brings the % to about 52% for having the same birthday. 56 will raise it above 99% 357 (leap year .. not sure how feb 29 would be handled for a birthday?) should leave you covered. I'm not sure which answer you are looking for. |
thoughtsexplorer![]() Elite user Elite... not D-Lite! 424 Posts ![]() |
You were both right.
SlimKing, I found thread, thanks for the info |
airship![]() Inner circle In my day, I have driven 1594 Posts ![]() |
BTW, this makes a great bar bet. If there are 30 people in a bar, it's pretty definite you'll win the bet that two of them have the same birthday. Not only will you get a free drink, you'll also meet lots of people going around to different tables explaining the bet and gathering birthdays.
'The central secret of conjuring is a manipulation of interest.' - Henry Hay
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