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The Magic Cafe Forum Index » » Rings, strings & things » » Professors Nightmare rope length (0 Likes) Printer Friendly Version

the sean
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Toronto, Ontario
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Hello I was wondering if someone could tell me the length of the ropes used in the Professors Nightmare?
I already know how to perform this effect, but I lost my ropes and I don't want to fork over 15 dollars just for a rope and some instructions I already have in my head.

Thanks in advance. Sean Smile Smile Smile
Jay
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Northern New Jersey
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Sean:

(A+C)/2=B

Jay Smile
Stanyon
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Landrum, S.C. by way of Chicago
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Now for the mathematically challenged:

Rope "A" = 8 inches

Rope "B" = 16 inches

Rope "C" = 32 inches

(These lengths are for example only. Your lengths my vary!) Smile

Cheers!
Stanyon

aka Steve Taylor

"Every move a move!"

"If you've enjoyed my performance half as much as I've enjoyed performing for you, then you've enjoyed it twice as much as me!"
Jay
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Northern New Jersey
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Hey Stanyon, shouldn't rope "B" be 20 inches in your example? Maybe I'm the mathematically challenged one here!

Smile Smile Smile

Jay Smile
Turk
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Portland, OR
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Jay,

I agree, the three ropes have to each end up as "equal" in length. Hence, the total of the shortest rope and the longest rope divided by 2 would have to equal the length of the "middle" rope.

Perhaps, a simpler method (for us mathematically challanged magicians) would be to just take a long length of rope of approximately 5 foot in length, fold it into "three equal lenghts", cut one length at the loop (this will be the middle piece, piece "B") and, from the remaining "double length" of rope, cut off a short piece of rope about 8"-10" (this is the short piece, piece "A") and the remaining longest piece becomes the longest piece of rope for the routine (piece "C"). Using this method does not require that you use any fixed lengths for your formula.

Turk
Magic is a vanishing Art.

This must not be Kansas anymore, Toto.

Eschew obfuscation.
Stanyon
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Landrum, S.C. by way of Chicago
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Quote:

On 2003-04-02 23:38, Jay wrote:
Hey Stanyon, shouldn't rope "B" be 20 inches in your example? Maybe I'm the mathematically challenged one here!



Okay Jay! You made me get out my ropes and measure them. Smile They are as follows:

Rope "A" Short = 15 inches

Rope "B" Medium = 32 inches

Rope "C" Long = 52 inches

When performed they are all equal at the critical moment! Smile

So I guess that mine's bigger than yours! Smile

Cheers!
Stanyon

aka Steve Taylor

"Every move a move!"

"If you've enjoyed my performance half as much as I've enjoyed performing for you, then you've enjoyed it twice as much as me!"
RayBanks
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Nassau Bay, TX
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Here is a good way of making the ropes "on the fly" as part of another routine:

http://www.allmagic.com/magicshow/rope/pnsetup.html

I tried it and it works pretty well
Smile
-------------
Pick a card, any card...No. not THAT one...THIS one

Ray Banks
ferraroj
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| | | I don't know if this drawing will
| |_| make any sense but an easy way
| | | to make the ropes is to cut the
| | | long rope (the one of the far left).
| | | Then cut the short rope (the top part
| | | Of the two top ends). Loop the
| | | reminder through the short rope and
| | | pull till it equals the long rope.
Cut at that point.
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