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The Magic Cafe Forum Index » » Penny for your thoughts » » Marc Paul - ACAAN Eyewitness Account (1 Likes) Printer Friendly Version

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InfinityDream
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Quote:
On 2010-04-19 16:50, canastafan wrote:
Marc Paul is a friend and student of David Berglas. I have personally witnessed David perform this effect many times, always as described and never misses. I have also seen Marc Paul perform the effect on England TV's Parkinson Show on YouTube. No stooges, no ifs & buts.

Just because you can't explain something, doesn't mean it's impossible. That's magic.

Solomon


Yes, it is very hard missing a beat with the p**-s***.
If this version is perfect why he doesn't try to sell it?

-Antonio
lunatik
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I think Waterloo is correct. If not, anyone can perform acaan. Just ask someone to shuffle the deck, name a card and position and BAM there she is!!! There is no method, it just works!!!
"Don't let your Dreams become Fantasies"
Dr. Eamon
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--------eXtrementalism--------......IT'S ALL IN YOUR MIND.....
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Quote:
On 2010-04-19 16:50, canastafan wrote:
Marc Paul is a friend and student of David Berglas. I have personally witnessed David perform this effect many times, always as described and never misses. I have also seen Marc Paul perform the effect on England TV's Parkinson Show on YouTube. No stooges, no ifs & buts.

Just because you can't explain something, doesn't mean it's impossible. That's magic.

Solomon


You are funny...
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Unicorn
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I am not so sure that the version of ACAAN of Marc Paul is he same as David Berglas.
When I watched the video he did not appear to have the cards shuffled at the start. But I could be wrong as Matthew says that it was a borrowed deck and shuffled but when Marc did it on TV it wasn't as far as I could see
praetoritevong
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Quote:
On 2010-04-19 18:24, InfinityDream wrote:

Yes, it is very hard missing a beat with the p**-s***.
If this version is perfect why he doesn't try to sell it?

-Antonio


Some people have respect for the art, over the need to make money?

Just a suggestion.
Nicolino
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Stefano, you should send this out to some well versed members here first and ask for a review. If you get some big names' recommendation, then somebody might start consider buying your effect...
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innercirclewannabe
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Where did your assistant learn to shuffle? Smile

Maybe you should consider doing a recording in a "real world situation".

Nicolino is right - getting the " well known names involved" will do wonders for your sales. Particularly if the like it!

Good luck with it.....
Tá sé ach cleas má dhéanann tú sé cuma mhaith ar cheann.
innercirclewannabe
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Typo:

The = They.
Tá sé ach cleas má dhéanann tú sé cuma mhaith ar cheann.
Jamie D
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H Stefano,

Why not just start a thread of your own A.C.A.A.N? You may get more talk/reply's on it. I know that the whole A.C.A.A.N plot has been discussed to death but if it is as good as you say it is, then it deserves its own thread as well, no? If possible, maybe make a real world video of you performing this, I do feel like it may have great potential.

Congrats on your achievement,

Darren
Twitter @darjames
brehaut
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Quote:
On 2012-03-25 15:00, Darren James wrote:
H Stefano,

Why not just start a thread of your own A.C.A.A.N? You may get more talk/reply's on it. I know that the whole A.C.A.A.N plot has been discussed to death but if it is as good as you say it is, then it deserves its own thread as well, no? If possible, maybe make a real world video of you performing this, I do feel like it may have great potential.

Congrats on your achievement,

Darren


That makes a lot of sense. Would love to see your own thread on this topic
JanForster
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Vedete, Stefano è sparito... Smile Jan
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shoexboy
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That is really Amazing if the ACAAN could shffled by spectector
Peter_turner
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Quote:
On 2010-03-29 12:36, Waterloophai wrote:
Please people, lets stay with our feet on the ground.
All the mumbo jumbo about the so called "perfect" Berglas effect is just not possible (apart from the 1 in 52 lucky chance).

When you ask a spectator (who is not a stooge) for his deck, you don't touch the deck and you ask the spectator to shuffle the deck, name a card and a number, there is NO way of knowing what card is at which place. It's that simple.

A stooge that can (false) shuffle the cards is enough to repeat the effect exactly as described. You may even ask the name or the number to someone else first if your stooge knows a MD. You have to do nothing, apart of receiving the applause...


Think outside the box Smile

Pete
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I agree with Pete, it's amazing what one can do when he or she thinks outside the box!

Regards,
Mike
boydy
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Here's my story.

So I was practicing a few moves with my cards a while back in the house while on the sofa with my girlfriend.
I decided to try the perfect demonstration of ACAAN so I had her shuffle the cards as may times as she wished then name a card then number...
I got her to deal to that number and turn the card over, it was not her named card. She turned the next card over and IT WAS HER CARD.

I calmly just winked at her.

I was as shocked as she was. Just plain luck.
No chance of that happening again LOL!
brehaut
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Quote:
On 2012-04-17 10:40, boydy wrote:
Here's my story.

So I was practicing a few moves with my cards a while back in the house while on the sofa with my girlfriend.
I decided to try the perfect demonstration of ACAAN so I had her shuffle the cards as may times as she wished then name a card then number...
I got her to deal to that number and turn the card over, it was not her named card. She turned the next card over and IT WAS HER CARD.

I calmly just winked at her.

I was as shocked as she was. Just plain luck.
No chance of that happening again LOL!


Anyone know what the odds if someone names a random card and number that the card will be either: 1) at the selected number 2) immediately before the selected number 3) immediately after the selected number 4) the card is the top card or 5) the card is the bottom card?
mastermindreader
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1 out of 10.4 times it will be at one of the positions named.

Each of the five possibilities you listed has odds of 1 out of 52. Thus, the odds of anyone of them occurring are 5 out of 52 or 1 out of 10.4.

Or so it seems to me. Smile

Bob
bremen79
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Quote:
On 2012-04-17 11:21, brehaut wrote:
Anyone know what the odds if someone names a random card and number that the card will be either: 1) at the selected number 2) immediately before the selected number 3) immediately after the selected number 4) the card is the top card or 5) the card is the bottom card?


For all of them is 1/52, the random number plays no role (unless the random number is 1 or 52, decreasing the number of positions from 5 to 4).
I think the overall probability that the named card in any of the 5 positions above (or any other 5) is 5/52.
Explanation: the probability that is in any of the 5 places is equal to 1 minus the probability that is in none of the five places that is 1 - (52-5)/52=5/52.
Francesco

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bremen79
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Quote:
On 2012-04-17 11:32, mastermindreader wrote:
Or so it seems to me. Smile

Bob


Correct! Mastermindreader you just anticipated me by few minutes, or maybe you read my mind while I was writing it Smile
Francesco

"I'm not going to censor myself to comfort your ignorance" Jon Stewart
brehaut
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Quote:
On 2012-04-17 11:32, mastermindreader wrote:
1 out of 10.4 times it will be at one of the positions named.

Each of the five possibilities you listed has odds of 1 out of 52. Thus, the odds of anyone of them occurring are 5 out of 52 or 1 out of 10.4.

Or so it seems to me. Smile

Bob


Thanks Bob
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