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The Magic Cafe Forum Index » » Shuffled not Stirred » » Yelnif 2 card "Suitability" trick (0 Likes) Printer Friendly Version

glowball
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Effect:
The magician "shuffles" the deck and gets 2 to 4 spectators on stage and magician turns his back and has a spectator cut the deck several times and then the spectator takes the top card. Then the other spectator(s) take a card from the top. Magician asks that all cards including the deck be hidden from his view and then he turns and faces his spectators on the stage. From any two consecutive spectators the magician asks what suit they have. The magician thinks, then writes the names of all their cards on a sheet of paper in his notebook. He tears it out and gives it to one of the spectators to read aloud as they confirm it is correct!

The below is my concoction of a 16 card de Bruijn type of quadrinary (1,2,3,4 ie: c,h,s,d) scheme (please forgive me if someone has already done this 2 suit approach) of every two cards having a unique pattern in regards to the two suits. I'm calling this "Yelnif2CS 16 card" deck just so I can keep up with all the de Bruijn's flying around. Repeat the same 16 cards two more times to give a 48 card deck and have a cheat sheet (see "Line1" and "Line2" below) to go with it secretly in your notebook. Note: the original 1928 "Suitability" trick by Larsen and Wright had 3 cards taken but they had a full 52 card deck with no duplicate cards.

After the two spectators tell you their suits then look at Line1 and find their two suits together and then look directly below at Line2 to know the first spectator's card.
The second spectator's card is horizontally to the right of the first spectator's card.

Line1 below shows the two suits that the 2 consecutive spectators tell you.
Line2 below are the actual Yelnif2CS 16 cards for the sequence.

Line1: Sc cd dh hs ss sh hd dd ds sd Dc Cc Ch hh hc cs.
Line2: 5s 9c Jd 4h Ts 3s 6h Ad 5d 7s 8d Qc 2c 3h Kh 4c.

The above line is a connected wrapping de Bruijn type arrangement.

If you had a third spectator take a card (you don't ask for the suit of the third spectator) just look to the right of the second spectator's card on Line2.
If you had a fourth spectator take a card (you don't ask for the suit of the fourth spectator) just look to the right of the third spectator's card on Line2.

You can even have 4 spectators take a card from the cut and then ask the middle two spectators to tell you their suits. Example: let's call the spectators A, B, C, and D. You ask for spectator B's suit and she says it is Spades. You ask for spectator C's suit and he says it is Diamonds. You then look along Line1 for "sd" and then look directly below and see "7s" therefore you know that spectator B's card is the 7 of Spades. Looking one place to the right you see spectator C's card is the 8 of Diamonds, one more place to the right you see spectator D's card is the Queen of Clubs. You also look to the LEFT of spectator B's 7s and see that spectator A's card is the 5 of Diamonds!

Repeat the above Yelnif2CS 16 cards three times to give a 48 card deck or do the trick with just 16 cards.

glowball yelnif
glowball
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Actually you can do this trick where the two Spectators do not have to be sequentially next to each other. In our example above suppose that the magician asks spectator B and spectator D for the names of their suits and that spectator "B" says "Spades" and spectator "D" says "Clubs". Then look along Line2 for the first Spade occurrence and then see if there is a Club precisely two notches away and if not then continue your visual scan for the next Spade occurrence and when you find that situation you know you have your first verbal spectator's card (in this example spectator "B"s card the Seven of Spades).

Note that there will only be four places on Line2 that will have the first verbal (B) spectator's suit, in this example it happened to be the 4th Spade and the Queen of Clubs two notches away is the second verbal (D) spectator's card.
glowball
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Nashville TN
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My prior post has a glitch (my first post is OK).
Below cheat sheet is for my second post, the "ask spectator B and D" method (the "two spectators apart method"):

Line1: Sd Ch ds hs sh sd hd ds dd sc dc ch ch hc hs Cc sd ch ds hs sh
Line2: 5s 9c Jd 4h Ts 3s 6h Ad 5d 7s 8d qc 2c 3h Kh 4c 5s 9c Jd 4h Ts

The two apart "ask spectator B and D" two card Suitablity method has a glitch: 9c, Qc and 2c all three have "ch" pattern.

If the two asked spectators say "Clubs" and "Hearts" (using the above two apart method) then say "I'm having trouble with these two" and ask the middle person what their suit is so you can determine whether the first person who was asked (first vocal person in the row) has the 9 of Clubs, Queen of Clubs or the two of Clubs. If the middle person has a Diamond then the first vocal person has the 9 of Clubs, if the middle person has a Heart then the first vocal person has the Two of Clubs otherwise the first vocal person has the Queen of Clubs.

Or you can be safe and NOT do the 2 spectators apart method and just do the first cheat sheet method in my first post (ask two consecutive spectators since that method is fine).
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